Sunday, April 30, 2017

Delete locked files OSX El Capitan

Delete locked files OSX El Capitan


Seems our lil captain decided to change some bits that usually were easier to do, before.

Deleting locked files in any of Apple OSs has been quite fun, meaning it wasnt easy to do.
From checking file permissions and modifying them (very old OSs) to pressing the right shortcut while accusing the trash bin, which IMHO, that was the easiest.

Well apparently they updated the process (or at least I havent found a better one), no shortcuts and of course I didnt even try the permissions path... waste of time even if it works.

So open your trash bin, select the locked file you got a warning for, right-click on it and voila... youll get the alternate menu:


Find the "Delete Immediately..." option, and click it.
It will prompt just a confirmation message, accept it and ready... file gone.
"That easy"

Still dont get why shall I have to open the damn trash bin, find, select, click, click, accept, for each locked file (or folder, also tested it), but thats Apples logic now.

So go ahead, start deleting the shaizen out of your bin, just remember to be careful, whats gone... its gone (not really, but thats for another post) ;)

S.

Read more »

Deerhunter 2014 for Mac

Deerhunter 2014 for Mac


DeerHunter 2014 is a free-to-play  3D hunting simulator and first person shooter (FPS) game developed by Glu Games. The game features a range of different animals you can hunt.



"Deer Hunter 2014 sees you travel from North America�s Pacific Northwest to the Savannah of Central Africa in an epic journey to hunt the world�s most exotic animals. There are over 100 animal species to hunt including bears, wolves, and cheetahs. You can collect trophies and win Game Center achievements, and see how you rank on the leader boards. Deer Hunter 2014 is free to play, but it does include some in-game purchase options."

System Requirements

Mac OS X 10.6 Snow Leopard or newer
Intel processor
300MB hard disk space

Free download at softonic.com
Read more »

Dead Rising 2

Dead Rising 2


Finally this game arrives, and in order for you to get Dead Rising 2 working with your logitech rumblepad 2 or dual action game pad you just need to download and copy the following files into the installation directory as follows...

http://rapidshare.com/files/422778312/x360ce.vibmod.3.1.4.1.rar

C:Program FilesCapcomDead Rising 2

x360ce.ini
xinput1_3.dll
XInputTest.exe

Btw, I only found it to work with 3.1.4.1, and no other older version, Now you can enjoy this with fill xbox 360 controller support, as it was made to enjoy... Lets go and slash zombies...
Read more »

Deletion in AVL Tree

Deletion in AVL Tree


 
The deletion of a data item from a data structure has always been difficult whatever data structure we use. The deletion is the inverse of insertion. In deletion there is a given value x and an AVL tree T. We delete the node containing the value x and rebalance the tree if it becomes unbalance after deleting the node. We will see that the deletion of a node is considerably more complex than the insertion of a node. It is complex in the sense that we may have to do more than one rotations to rebalance the tree after deleting a node. We will discuss the deletion case by case and will see that about what points we have to take care in the deletion process.
We are not going to write the code for deletion here. If we have to use AVL tree routines or class, the deletion and insertion routines of AVL tree are available in standard library. We can use these routines in our program. We have no need to write these routines. But here we discuss these to understand their functionality.
We know that insertion in a height-balanced tree requires at most one single rotation or one double rotation. We do this rotation at the node whose balance violates the AVL condition. We can use rotations to restore the balance when we do a deletion. If the tree becomes unbalance after deleting a node then we use rotations to rebalance it. We may have to do a rotation at every level of the tree. Thus in the worst case of deletion we have to do log2 N rotations. As log2 N is the number of levels of a tree of N nodes.
Let�s consider an example of deleting a node from a tree. In this example, we will discuss the worst case of deletion that is we have to do rotation at each level after deleting a node. Look at the following figure i.e. Fig 23.8. In this figure the root of the tree is node N and we have expanded only the left subtree of this node. The right subtree of it is indicated by a triangle. We focus on the left subtree of N. The balance of each non-leaf node of the left subtree of N is �1. This means that at every non-leaf node the depth/height of left subtree is one shorter than the height of right subtree. For example look at the node C. The left subtree of C is one level deep where as it�s right subtree is two levels deep. So balance of it is 1 � 2 = -1. If we look at node I its left subtree has height 2 as there are two levels where nodes G and H exists. The right subtree of I has number of levels (i.e. height) 3 where exists the nodes K, L and M respectively. Thus the balance of I is 2 � 3 = -1. Similarly we can see that other nodes also have the balance �1. This tree is shown in the following figure.
clip_image001
Here in this tree, the deletion of node A from the left subtree causes the worst case of deletion in the sense that we have to do a large number of rotations. Now we delete the node A from the tree. The effect of this deletion is that if we consider the node C the height of its left subtree is zero now. The height of the right subtree of C is 2. Thus the balance of C is 2 now. This makes the tree unbalance. Now we will do a rotation to make the tree balanced. We rotate the right subtree of C that means the link between C and D so that D comes up and C goes down. This is mentioned in the figure below.
clip_image002
After this rotation the tree has transformed into the following figure. Now D becomes the left child of F and C becomes the left child of D.
clip_image003
By looking at the inorder traversal of the tree, we notice that it is preserved. The inorder traversal of the tree before rotation (i.e. fig 23.8) is C D E F G H I J K L M N. Now if we traverse the tree after rotation (i.e. fig 23.9) by inorder traversal we get C D E F G H I J K L M N, which is the same as it was before rotation.
After this rotation we see that the tree having D as root is balanced. But if we see the node F we notice that the height of its left subtree is 2 and height of its right subtree is 4. Thus the balance of F is �2 (or 2 if we take the absolute value) now. Thus the tree becomes unbalance. So we have to do rotation again to balance the tree. The whole left subtree of F is shorter so we do the left rotation on the link of F and I (in the tree in fig 23.9) to bring F down and I up so that the difference of height could be less. After rotation the tree gets the new form that is shown in the figure below.
clip_image004
Here we see that the nodes G and H, which were in the left subtree of I, now become the right subtree of F. We see that the tree with I as root is balanced now. Now we consider the node N. We have not expanded the right subtree of N. Although we have not shown but there may be nodes in the right subtree of N. If the difference of heights of left and right subtree of N is greater than 1 then we have to do rotation on N node to balance the tree.
Thus we see that there may be such a tree that if we delete a node from it we have to do rotation at each level of the tree. We notice that we have to do more rotations in deletion as compared to insertion. In deletion when we delete a node we have to check the balance at each level up to the root. We do rotation if any node at any level violates the AVL condition. If nodes at a level do not violate AVL condition then we do not stop here we check the nodes at each level and go up to the root. We know that a binary tree has log2 N levels (where N is total number of nodes) thus we have to do log2 N rotations. We have to identify the required rotations that mean we have to identify that which one rotation out of the four rotations (i.e. single left rotation, single right rotation, double right-left rotation and double left-right rotation) we have to do. We have to identify this at each level.
We can summarize the deletion procedure as under.
Delete the node as in binary search tree. We have seen in the discussion of deleting a node from a BST that we have three cases, which we discussed as follows
Case I: The node to be deleted is the leaf node i.e. it has no right or left child. It is very simple to delete such node. We make the pointer in the parent node pointing to this node as NULL. If the memory for the node has been dynamically allocated, we will release it.
Case II: The node to be deleted has either left child (subtree) or right child (subtree).
In this case we bypass the node in such a way that we find the inorder successor of this node and then link the parent of the node to be deleted to this successor node. Thus the node was deleted.
Case III: The node to be deleted has both the left and right children (subtree). This is the most difficult case. In this case we find the inorder successor of the node. The left most node of the right subtree will be the inorder successor of it. We put the value of that inorder successor node into the node to be deleted. After it we delete the inorder successor node recursively.
In deletion in AVL tree, we delete the node as we delete it in a BST. In third case of deletion in BST we note that the node deleted will be either a leaf or have just one subtree (that will be the right subtree as node deleted is the left most subtree so it cannot have a left subtree). Now we are talking about deletion in an AVL tree. Since this is an AVL tree so if the deleted node has one subtree that subtree contains only one node. Why it is so? Think about its reason and answer.
After deleting the node we traverse up the tree from the deleted node checking the balance of each node at each level up to the root. Thus the deletion in AVL tree is like the deletion in BST except that here in AVL tree we have to rebalance the tree using rotations.

Cases of Deletion in AVL Tree

Now let�s consider the cases of deletion that will help to identify what rotation will be applied at what point.
There are 5 cases to consider. Let�s go through the cases graphically and determine what actions are needed to be taken. We will not develop the C++ code for deleteNode in AVL tree. This is left as an exercise.
Case 1a:
The first case is that the parent of the deleted node had a balance of 0 and the node was deleted in the parent�s left subtree.
In the following figure (Fig 23.12) the left portion shows the parent node with a horizontal line in it. This horizontal line indicates that the left and right subtrees of this node have the same heights and thus the balance of this node is 0. When we delete a node from its left subtree then height of its right subtree becomes larger than the left subtree. The right portion in the figure shows this. We are showing a symbol instead of balance of node inside the node. The notation (symbol) in the node indicates that the height of left subtree is shorter than the height of right subtree of the node.
clip_image005
Now the action that will be taken in this case is that, change the balance of the parent node and stop. No further effect on balance of any higher node. There is no need of rotation in this case. Thus it is the easiest case of deletion.
Let�s consider an example to demonstrate the above case.
Consider the tree shown in the following figure i.e. Fig 23.13. This is a perfectly balanced tree. The root of this tree is 4 and nodes 1, 2 and 3 are in its left subtree. The nodes 5, 6 and 7 are in the right subtree.
clip_image006
Consider the node 2. We have shown the balance of this node with a horizontal line, which indicates that the height of its left subtree is equal to that of its right subtree. Similarly we have shown the balance of node 4.
Now we remove the node 1 which is the left subtree of node 2. After removing the left child (subtree) of 2 the height of left subtree of 2 is 0. The height of right subtree of 2 is 1 so the balance of node 2 becomes �1. This is shown in the figure by placing a sign that is down ward to right side, which indicates that height of right subtree is greater than left subtree. Now we check the node 4. Here the height of left subtree of it is still 2. The height of its right subtree is also 2. So balance of the node 4 is 0 that is indicated by the small horizontal line (minus sign) in the figure below. Here we don�t need to change the balance of 4.
clip_image007
clip_image008clip_image009clip_image010clip_image011clip_image012
clip_image013 clip_image014
clip_image015
Fig 23.14: Tree before and after deleting node 1
Case 1b:
This case is symmetric to case 1a. In this case, the parent of the deleted node had a balance of 0 and the node was deleted in the parent�s right subtree. The following figure shows that the balance of the node was zero as left and right subtree of it have the same heights.
clip_image016
After removing the right child the balance of it changes and it becomes 1, as the height of its left subtree is 1 greater than the height of right subtree. The action performed in this case is the same as that in case 1a. That is change the balance of the parent node and stop. No further effect on balance of any higher node.
The previous example can be done for this case only with the change that remove the right child of node 2 i.e. 3.
Case 2a:
This is the case where the parent of the deleted node had a balance of 1 and the node was deleted in the parent�s left subtree. This means that the height of left subtree of the parent node is 1 greater than the height of its right subtree. It is shown in the left portion of the figure below.
clip_image017 clip_image017[1] clip_image017[2] clip_image017[3]
clip_image018
Now if we remove a node from the left subtree of this node then the height of left subtree will decrease by 1 and get equal to the height of right subtree. Thus the balance of this node will be zero. In this case, the action that we will perform to balance the tree is that change the balance of the parent node. This deletion of node may have caused imbalance in higher nodes. So it is advised to continue up to the root of the tree. We will do rotation wherever the balance of the node violates the AVL condition.
There are five cases to consider while deleting a node of an AVL tree. When a node is deleted, the tree can become unbalanced. We calculate the balance factor of each node and perform rotation for unbalanced nodes. But this rotation can prolong to the root node. In case of insertion, only one node�s balance was adjusted as we saw in previous lectures but in case of deletion, this process of rotation may expand to the root node. However, there may also be cases when we delete a node and perform no or one rotation only.
Now, we will see the five cases of deletion. A side note is that we are not going to implement these cases in C++ in this lecture, you can do it yourself as an exercise with the help of the code given inside your text book. In this lecture, the emphasis will be on the deletion process and what necessary actions we take when a node is required to be deleted from an AVL tree. Actually, there are two kinds of actions taken here, one is deletion and the other one is the rotation of the nodes.
Case 1a: The parent of the deleted node had a balance of 0 and a node was deleted in the parent�s left subtree.
clip_image001[4]
In the left tree in the Fig 24.1, the horizontal line inside the tree node indicates that the balance is 0, the right and left subtrees of the node are of equal levels. Now, when a node is deleted from the left subtree of this node, this may reduce by one level and cause the balance of the right subtree of the node to increase by 1 relatively. The balance of the node in favor of the right subtree is shown by a triangular knob tilted towards right. Now, the action required in this case to make the tree balanced again is:
Change the balance of the parent node and stop. There is no further effect on balance of any higher node.
In this case, the balance of the tree is changed from 0 to �1, which is within the defined limits of AVL tree, therefore, no rotation is performed in this case.
Below is a tree in which the height of the left subtree does not change after deleting one node from it.
clip_image003[4]
The node 4 is the root node, nodes 2 and 6 are on level 1 and nodes 1, 3, 5, 7 are shown on level 2. Now, if we delete the node 1, the balance of the node 2 is tilted towards right, it is �1. The balance of the root node 4 is unchanged as there is no change in the number of levels within right and left subtrees of it. Similarly, there is no change in the balances of other nodes. So we don�t need to perform any rotation operation in this case.
Let�s see the second case.
Case 1b: the parent of the deleted node had a balance of 0 and the node was deleted in the parent�s right subtree.
clip_image004[4]
On the left of Fig 24.3, the tree is within the balance limits of AVL. After a node is deleted from the right subtree of it. The balance of the tree is tilted towards left as shown in the right tree show in the Fig 24.3. Now, we see what action will be required to make the tree balanced again.
Change the balance of the parent node and stop. No further effect on balance of any higher node (same as 1a).
So in this case also, we don�t need to perform rotation as the tree is still an AVL (as we saw in the Case 1a). It is important to note that in both of the cases above, the balance of the parent node was 0. Now, we will see the cases when the balance of the parent node is not 0 previously.
Case 2a: The parent of the deleted node had a balance of 1 and the node was deleted in the parent�s left subtree.
clip_image005[4]
In the Fig 24.4 above, the tree on the left contains the balance factor as 1, which means that the left subtree of the parent node is one level more than the number of levels in the right subtree of it. When we delete one node from the left subtree of the node, the height of the left subtree is changed and the balance becomes 0 as shown in the right side tree of Fig 24.4. But it is very important understand that this change of levels may cause the change of balance of higher nodes in the tree i.e.
Change the balance of the parent node. May have caused imbalance in higher nodes so continue up the tree.
So in order to ensure that the upper nodes are balanced, we calculate their balance factors for all nodes in higher levels and rotate them when required.
Case 2b: The parent of the deleted node had a balance of -1 and the node was deleted in the parent�s right subtree.
Similar to the Case 2a, we will do the following action:
Change the balance of the parent node. May have caused imbalance in higher nodes so continue up the tree.
Now, we see another case.
Case 3a:The parent had balance of -1 and the node was deleted in the parent�s left subtree, right subtree was balanced.
clip_image007[4]
As shown in the left tree in Fig 24.5, the node A is tilted towards right but the right subtree of A (node B above) is balanced. The deleted node lies in the left subtree of the node A. After deletion, the height of the left subtree is changed to h-1 as depicted in the right tree of above figure. In this situation, we will do the following action:
Perform single rotation, adjust balance. No effect on balance of higher nodes so stop here.
After single left rotation, we have the tree as shown in the figure below.
clip_image009[4]
Node A has become the left subtree of node B and node 2 left subtree of node B has become the right subtree of node A. The balance of node B is tiled towards left and balance of node A is tilted towards right but somehow, both are within AVL limits. Hence, after a single rotation, the balance of the tree is restored in this case.
Case 4a: Parent had balance of -1 and the node was deleted in the parent�s left subtree, right subtree was unbalanced.
clip_image011[4]
In the last case 3a, the right subtree of node A was balanced. But in this case, as shown in the figure above, the node C is tilted towards left. The node to be deleted lies in the left subtree of node A. After deleting the node the height of the left subtree of node A has become h-1. The balance of the node A is shown tilted towards right by showing two triangular knobs inside node A. So what is the action here.
Double rotation at B. May have affected the balance of higher nodes, so continue up the tree.
By performing double rotation in the tree above, we have the following tree.
clip_image013[4] Read more »

Debbie have you seen Kenneth Oppels EVERY HIDDEN THING

Debbie have you seen Kenneth Oppels EVERY HIDDEN THING


A reader writes to ask if Ive seen Kenneth Oppels Every Hidden Thing. Due out on October 11, 2016 from Simon & Schuster (one of the "Big Five" publishers), it has Native content.

When I do these "Debbie--have you seen" posts, I usually copy the description of the book, but this time, it doesnt help! The Native content is not included in the description, which I find a bit ironic, given that the word "hidden" is in the books title:

The hunt for a dinosaur skeleton buried in the Badlands, bitter rivalries, and a forbidden romance come together in this beautifully written new novel that�s Romeo and Juliet meets Indiana Jones.
Somewhere in the Badlands, embedded deep in centuries-buried rock and sand, lies the skeleton of a massive dinosaur, larger than anything the late nineteenth century world has ever seen. Some legends call it the Black Beauty, with its bones as black as ebony, but to seventeen-year-old Samuel Bolt it�s the �rex�, the king dinosaur that could put him and his struggling, temperamental archaeologist father in the history books (and conveniently make his father forget he�s been kicked out of school), if they can just quarry it out.

But Samuel and his father aren�t the only ones after the rex. For Rachel Cartland this find could be her ticket to a different life, one where her loves of science and adventure aren�t just relegated to books and sitting rooms. Because if she can�t prove herself on this expedition with her professor father, the only adventures she may have to look forward to are marriage or spinsterhood.

As their paths cross and the rivalry between their fathers becomes more intense, Samuel and Rachel are pushed closer together. And with both eyeing the same prize, their budding romance seems destined to fail. But as danger looms on the other side of the hills, causing everyone�s secrets to come to light, Samuel and Rachel are forced to make a decision. Can they join forces to find their quarry�and with it a new life together�or will old enmities and prejudices keep them from both the rex and each other?



See? Nothing there that references Native content. Reviews, however, provide more information. These are excerpts from the Barnes and Noble page for Every Hidden Thing.

Publishers Weeklys review says (in part):
As their friendship develops into romance, their camps are endangered by the local Sioux tribe after Rachel and her father remove relics from a burial site.

School Library Journals review says (in part)
... the rival camps must also deal with realities of life in the historical American Wild West: lack of supplies, possibility of wildfires, and potential violence at the hands of the "badlands" inhabitants (often referred to as natives, Indians, or Sioux). 

And, the Kirkus review says
Rachel�s narrative reveals that she�s one of the few white characters with enough conscience to reflect on the savagery of the explorers� treatment of the local Pawnee and Lakota Sioux.

I reviewed Oppels The Boundless last year and found serious problems with it. If I get a copy of Every Hidden Thing, Ill be back.
Read more »

Deadman Wonderland 01 13

Deadman Wonderland 01 13


http://i1266.photobucket.com/albums/jj533/anonymous0505/homen-morto.jpg

Epis�dio 01 - 12 + Ova
Tamanho: 80-101 MB
Qualidade: Boa

Formato: MP4 - MKV
Uploader: Alex Sedu��o
~Deadman Wonderland � Epis�dio 01-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 02-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 03-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 04-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 05-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 06-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 07-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 08-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 09-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 10-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 11-12 Download: Mediafire
~Deadman Wonderland � Epis�dio 12-12 Download: Mediafire
~Deadman Wonderland � OVA Download: Mediafire
Read more »

DB2 Express C for Amazon EC2 updated with new interface

DB2 Express C for Amazon EC2 updated with new interface


Juice DB reports that the DB2 Express-C Amazon Machine Images (AMIs) for Elastic Compute Cloud (EC2) have been updated to 9.7.2. In addition to running the latest release of DB2 Express-C, they now include a simple web interface for the initial configuration in place of the older console-based approach.


Run these AMIs through Amazon DevPay:
  • Run DB2 Express-C 9.7.2 on Linux (32-bit)
  • Run DB2 Express-C 9.7.2 on Linux (64-bit)
DB2 Express-C is a free product. There are no license fees, but you do have to pay Amazon for its hosting.

Once subscribed, you can launch them with the AMI ids below.

US Region:
32-bit ami-1b30db72 ec2-dev-ibm-images/ibm-db2-express-c-9.7.2-32-bit.manifest.xml
64-bit ami-1930db70 ec2-dev-ibm-images/ibm-db2-express-c-9.7.2-64-bit.manifest.xml


AP Region:
32-bit ami-97c7b8c5 ec2-dev-ibm-images-ap/ibm-db2-express-c-9.7.2-32-bit.manifest.xml
64-bit ami-7bc6b929 ec2-dev-ibm-images-ap/ibm-db2-express-c-9.7.2-64-bit.manifest.xml


Resources
  • View quickstart video (older interface)
  • Run Ubuntu-based AMIs
  • Download DB2 Express-C
Read more »

Death Vomit

Death Vomit


Powered By : Reverbnation
DEATH VOMIT

Read more »

Saturday, April 29, 2017

Day One Garry Incident Full Free Download Game

Day One Garry Incident Full Free Download Game


 

Day One Garry Incident Full Free Download Game 

Size: 2.535 GB 

 



 

Download Day One Garry Incident Full PC Game 

About This Game 

 Garry Friedman, a veteran bush pilot in his early 40s, still divides emotionally after a tragic accident involving his wife and daughter, chokes alcohol every night to escape his torment. 

Download

Read more »

Dear Scholastic This Is A Test

Dear Scholastic This Is A Test


I have a lot of thoughts in my head this morning, about yesterdays #StepUpScholastic chat on Twitter, and about the Step Up Scholastic campaign, but I am starting with this:

Stone Fox is in 10 bks/$10 box
Last year, Scholastic, working with WNDB, put together a flyer of books specific to diversity. In theory, terrific marketing! BUT.

When I saw the first page of the flyer, I wasnt happy at all to see Stone Fox on it. That book has stereotyping of Native peoples in it, and as such, is the opposite of what kids need if theyre to 1) see mirrors of who they are, or 2) see accurate depictions of those who are unlike themselves. With that book on there, Scholastic and WNDB are marketing a problematic book. Stone Fox is in the 10 BOOKS FOR $10 box on bottom right of the flyer shown here.

Late yesterday, Scholastic announced an expansion of its partnership with We Need Diverse Books. Theyre going to do eight flyers this year. Will these flyers have Stone Fox? Will they have books by Native writers? When I looked inside last years flyer, I saw two books by Joseph Bruchac, but thats not enough.

Last years partnership, and this expansion of that partnership, are steps in the right direction but if Scholastic is seriously committed to diversity and providing children with books that truly educate--rather than ones that miseducate children about Native peoples--heres what they need to do (saying they in this post but I know Scholastic is reading this, so I could say YOU instead):
  1. Acquire more books by Native writers and put those books in the flyers, all year long, not just in the special flyers about diversity. And on the teacher webpages. And in book fairs. Maximize the distribution, here and around the globe, too. Last night I learned a little about the flyers you publish around the globe. Youre exporting stereotypes. That has to stop. 
  2. Seek out books by Native writers--books published by other publishers--and get them into the flyers. Do it now. Today. I understand theres "rights" issues associated with all this but also think that your billion+ revenue could be leveraged somehow to make this happen. Get them in the diversity flyers but in all flyers. Like I said above: all year round. Every grade level. Every month.
  3. Remove books that misrepresent Native peoples from all flyers and from their website, too. Theres absolutely no reason to continue to market Island of the Blue Dolphins. Or Hiawatha (the one by Susan Jeffers). Or Touching Spirit Bear. Or Sign of the Beaver. Or The Girl Who Loved Wild Horses. Or Julie of the Wolves. Or Indian in the Cupboard. Those are some of the books you distribute. STOP. And I know there are others, too. 
  4. Take some of that billion dollar revenue and hire people with expertise---not just in kidlit---but in Native Studies, to help you with all these tasks. Im not asking you to hire me. But I think I can help you find people who would work with you. All this money youre making, right here on what used to be Native lands... come on. Step Up. 

Ebony Elizabeth Thomas has been doing some writing about distinctions between marketing, advocacy, and activism that I find helpful as we all live through these periods of fighting for change in what we get from the publishing industry. The Scholastic flyers are marketing. I think it is marketing borne from activism, but as I noted above, theres a lot more to do with what Scholastic publishes, and what they choose to market.

Some people think I hate Scholastic. Some people think I hate white people. Neither is true. Last night I did a series of tweets about how much I love Shadowshaper and If I Ever Get Out of Here. I wanna see several of the people who made those two books possible, working in-house at Scholastic, getting us more books like that.

Ill be waiting to see the new flyers. Not just the diversity ones. Every single one. They are a way to measure what Scholastic is doing. Doing content analyses of the flyers provide us with a way to test what Scholastic is doing. The flyers, as I view them, are a test that--if passed--could win back the trust theyve lost.

__________

My post from last year: Books to get (and avoid) from the WNDB/Scholastic Reading Club Collaboration
Read more »

Dead or Alive

Dead or Alive





If theres one thing the PlayStation has a lot of, its fighting games. Good fighting games on the other hand are a different story. Tecmo just happens to have one of those different stories though, and it goes by the name of Dead or Alive.
Dead or Alive was originally released as an arcade game that ran on Segas Model 2 board (read Virtua Fighter 2) some time ago. A perfect arcade port later appeared on the Saturn in Japan and was considered one of the better fighting games on the system. The title has of course recently resurfaced on the PlayStation with a fresh new look, with new character models that look significantly better than the Saturn and arcade versions.
The game features nine playable characters from the get-go with two more attainable via total completion of the game. Every time you beat the game you are rewarded with a new outfit for one of the characters. There is a total of 84 costumes in all, which range from your typical karate gi to scuba gear. The design of the characters themselves isnt groundbreaking by any means, in fact some look suspiciously similar to characters from the Street Fighter, Tekken, and Virtua Fighter series.
Dead or Alives fighting engine is obviously influenced by Segas Virtua Fighter series, with its punch, kick, and hold button setup. The hold button is just that, a button that allows you to get your opponent in grappling holds. This is really kind of cool because you can counter holds and attacks and then reverse counters on top of that, so you sometimes can get an awesome Jackie Chan-style grappling match that goes back and forth three or four times till someone messes up and pays the consequences. It may sound complicated, but since the special moves are all fairly simple to perform, anyone can easily learn how to play.
Graphically, Dead or Alive is one of the nicest-looking PlayStation games to date. The character models are nearly seamless, meaning that the 3D characters dont appear to be blocky or made up of polygons. Instead, the characters have a very smooth, almost skinlike quality to them. Mixed with the fast and fluid motion of the character animations, this gives a stunning sense of realism. Apparently the designers went a little too far when it came to the motion design of the female characters though, because they made it so their breasts bounce while fighting. Honestly, if it werent for the fact that they keep on bouncing well after they should, it may have been seen as a commendable effort for the designers keen attention to detail. At any rate, the breast-bouncing can be turned off or on in the option menu. The sound effects and accompanying background music, while not up for any awards, get the job done.
Overall, Dead or Alive delivers a realistic fighting experience. Combining fantastic graphics and above-average gameplay, Dead or Alive is a fun and challenging fighting game well worth picking up. Hopefully, it wont be overshadowed too much by the US release of Namcos Tekken 3.
Read more »

DB2 sets industry performance record on an x86 64 server

DB2 sets industry performance record on an x86 64 server


DB2 9.5 just set a new industry record on the TPC-C benchmark of online transaction processing (OLTP) performance, running on an IBM server powered by standard x86-64 Intel Xeon processors. This is the first time that a database running on an Intel or AMD x86-64 system has ever broken the 1 million tpmC barrier. DB2 has exceeded that barrier by over 20%.

DB2 also broke new ground in the price/performance category, being the first database software to come in lower than $2 USD/tpmC.

The free DB2 Express-C database is built on the same codebase as this record-breaking edition of DB2.

Cheers,

Leons Petrazickis
DB2 Express-C Team
Read more »

De Joint Presents Palancing In We Section

De Joint Presents Palancing In We Section



                                                     Download







1. Police In De Section
2. Palance (Road Mix)
3. Yuh Want Some Sorrel
4. Pipe
5. Doh Hold Me Back
6. No Behaviour
7. Fetting On
8. Heaven
9. Ants In Yuh Pants
10. Melee
11. De Spanner
12. Steam
13. Anything
14. Anything (WIB DUB)
15. Thats How We Party
16. Alright (Remix)
17. Dis Gyal
18. Stalker
19. Party Hard (Remix)
20. I Know You Want Me (Bumper To Fender Remix)
21. Bumper To Fender
22. Pavement
23. Barm
24. Gone 
25. Girl
26. Staggerah
27. Staggerah (Dub Remix)
28. Theifin Tonight
29. Gimmie Soca
30. Start Wining
31. Shes Sexy Now
32. Murdah
33. Ah Drinka (Remix)
34. Slow Wine
35. Waist Line Roll
36. Wuk It
37. Call Me
38. Call On me (Soca Remix)
39. Wine To De Back
40. One Juk For De Carnival
41. Real Tight
42.Head Bad
43. Best Wine Of My Life
44. In Front Of Meh
45. Wine On Me (Hold Yuh Riddim)
Read more »

Death Battle! Lara Croft Vs Nathan Drake

Death Battle! Lara Croft Vs Nathan Drake


Boa noite, galera! Come�amos hoje, depois de um pequeno atraso, a quarta temporada do Death Battle, com o duelo �pico entre Lara Croft e Nathan Drake! Os epis�dios atrasados do Mesa vir�o em breve. Aproveitem e at� l�!

DEATH BATTLE!
Lara Croft Vs. Nathan Drake
Download (Full HD 1920x1080): Aqui
Download (HD 1280x720): Aqui
Download (640x360): Aqui
Read more »

Deadly Dozen Pacific Theater

Deadly Dozen Pacific Theater


http://www.megaupload.com/?d=212BPN50
http://www.megaupload.com/?d=RIWO4Z5D
Read more »

DEMAXIPERIA bikin MAXI mu selembut XPERIA D

DEMAXIPERIA bikin MAXI mu selembut XPERIA D



ijin share yah :) maaf kalo oot atau udah ada yang post :)

*DWYOR Semua kerusakan di tanggung penumpang :D
*Selalu backup sebelum meng otak-atik system
*Backup MMS.APK di system app karena message yg di push ada bug di setting tapi yg lain lancar
*yang ane share semua jalan alias tested :D
ok langsung aja cekibrot:
(img:2681473093441)

Syarat:
  • ROOT
  • ROM DEODEX 

Full ZIP:
1.Download dan install lewat CWM http://alturl.com/t5i3x
2.Download dan install widgetlockescreen http://tinyurl.com/demaxperia2
3.Download backupan ane http://tinyurl.com/demaxperia3
4.extrax zip backupan ane terus move k /sdcard/data/com.teslacoilsw.widgetlocker.backup
5.teruss masuk k aplikasi widgetlock tap setting pilih backup/restore pilih restore  pilih demaxperia
6.untuk lebih DEMAXIPERIA bisa pasang wallpaper nya :D http://tinyurl.com/demaxperia4
setelah itu tinggal ngoprek" lagi yang agan mau ^o^

Log di ZIP satu" ane sebutin plus link nya yah ^o^
inget set permisionnya :)
1.Boot animations Xperia http://alturl.com/xt3v2
(khusus shutdown tinggal rename jadi shutdown.zip)

2.Lockscreen http://alturl.com/4ji74

3.Launcher X-launch http://alturl.com/ya3rh

4.Message (bug setting) http://alturl.com/3eg6e

5.walkman http://alturl.com/epr5t

6.visualizer walkman http://alturl.com/iwgr8

7.walkman Facebook like http://tinyurl.com/demaxperia8

8.walkman edit info http://alturl.com/4t7ah

HAPPY MOODING ^0^

http://www.facebook.com/groups/smartfren.adromaxi.I/doc/450731661642717/
Read more »

DeskSpace v1 5 7 2 your Desktop Cube Widget

DeskSpace v1 5 7 2 your Desktop Cube Widget



Manage your Windows Desktop with this virtual 3D desktop manager "DeskSpace". Each side of the cube, which is 6, has different windows display. you can organize and manage both side of your desktop. allowing your desktop icons to hide or show on its side of 3d Desktop Windows.



Here are Some features of DesKSpace
    You can add hot key shortcut for fast switch in every windows.
  • Auto Switch Desktops when Windows Dragged Out Screen
  • Show cube When Activation Hot Key Pressed
  • Start When Windows Starts
  • Mouse Wheel To Rotate Cube to activate DeskSpace
  • can increase Zoom and Display for Normal to fast



Desktop Hot keys
  • Switch To Desktop 1: Ctrl + Alt + 1
  • Switch To Desktop 2: Ctrl + Alt + 2
  • Switch To Desktop 3: Ctrl + Alt + 3
  • Switch To Desktop 4: Ctrl + Alt + 4
  • Switch To Desktop 5: Ctrl + Alt + 5
  • Switch To Desktop 6: Ctrl + Alt + 6



Download DeskSpace.v1.5.7.2 Full

More Tags: Angry Bird, Blogger, Fate , Plants Vs Zombie, Special Force, Point Blank, Ai Maps, Deep Freeze UnFreezer, Ninja Saga, Deep Freeze, Samsung SGH, Guitar Pro, USB XP Install, Yahoo 443 Problem, Turtle Odyssey, GTA San-Andreas, PlayStation, Tips Tweaks Tricks, HTML, Facebook, Animated JPG, Counter-Strike, USB Windows Format, Screensaver, USB Security.
Read more »

Dead Space Bagaimana Cara Gampang Dapetin Power Nodes Credits

Dead Space Bagaimana Cara Gampang Dapetin Power Nodes Credits


Sesuai janji ane, ane akan membahas tentang cara gampang dapetin power nodes & credits di dead space android. Pertama-tama kita cari tau dulu apa itu credit & power node.

 Credits

Credits adalah alat pengganti uang di game dead space, yang bisa digunakan untuk membeli armor yang lebih kuat & persediaan peluru ataupun power nodes.

 Power Nodes

Power nodes adalah benda yang bisa digunakan untuk meng-upgrade persenjataan Vandal, meng-upgrade rig Vandal, & membuka pintu khusus.

Oke gak usah berlama-lama lagi, ini dia cara gampang dapetin barang2 diatas. Waktu agan lagi di suatu ruangan agan bisa liat2 kiri-kanan buat loker power nodes & Container yang bisa dihacurin yang bentuknya kayak gini:

Power Nodes Locker

Container

dan agan juga bisa cari loker biasa, container, & crates yang berisi peluru atau credits yang bentuknya begini:

Locker

Crates

Satu lagi, kalo agan lagi di jalan yang bercabang terus pake penunjuk jalan, jangan ambil jalan yang di tunjukin ama penunjuk jalannya, karena biasanya ada ruangan yang berisi power nodes, credits, peluru & lain2. Tenang aja, biasanya di tempat2 tersembunyi ga ada musuh yang tiba2 muncul paling2 halusinasi si Vandal aja. Selain itu kalo agan punya power nodes jangan di pake semua, sisain minimal satu aja buat ruangan khusus yang butuh power nodes buat ngebukanya. Biasanya di ruangan khusus yang dibuka pake power nodes berisi banyak credits, peluru, & kadang2 ada power nodes juga di dalamnya.

Oke gan segitu aja dulu, nanti ane akan ngebahas tantang bagaimana cara gampang bunuh necromoprhs & brutes dengan peluru minim. Semoga tips2 di atas bisa membantu gaming agan2 semua.

keep garu-ing......... :)
Read more »